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PV Work

What is the n...

Question

What is the net work done (is calories ) when 1 mole of monoatomic ideal gas undergoes in a process described by $1, 2, 3, 4$ in given $V - T$ graph Use: $R = 2 c a l / m o l e K$
$l n 2 = 0.7$

- 600 c a l

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- 660 c a l

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+ 630 c a l

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+ 600 c a l

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Solution

The correct option is A $+ 630 c a l$
$W = - n R T + l n \frac{V_{2}}{V_{1}}$
$= - 1 \times 2 \times 300 \times l n \frac{20}{10}$
$= - 600 \times l n 2$
$= - 600 \times (0.693 - 0.7)$
$= - 420 c a l$
for process 2,
$w = n C_{v} l n \frac{V_{2}}{V_{1}} \times (600 - 300)$
$w = 1 \times \frac{3 \times 2}{2} l n \frac{10}{20} \times (600 - 300)$
$w_{2} = 300 \times 3 \times 0.7 = 2.1 \times 300$
$w_{2} = - 630 c a l$
for process 3,
$v_{1} = 40 L, v_{2} = 10 L, T = 600 R$
$w = - n R T l n \frac{v_{2}}{v_{1}}$
$= - 1 \times 2 \times 600 l n \frac{40}{10}$
$= + 1200 \times 2 l n 2 = 1680 c a l .$
Net work $- 420 + 1680 - 630 = + 630 c a l$

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What is the net work done (is calories ) when 1 mole of monoatomic ideal gas undergoes in a process described by 1,2,3,4 in given V−T graph Use: R=2cal/moleKln2=0.7

What is the net work done (is calories ) when 1 mole of monoatomic ideal gas undergoes in a process described by $1, 2, 3, 4$ in given $V - T$ graph Use: $R = 2 c a l / m o l e K$
$l n 2 = 0.7$