Question

What is the no. of unpaired electrons in ${\mathrm{Mn}}^{2+}$ ion? At no. $\mathrm{Mn}=25$.

Answer 1

Manganese:

• Manganese is an element having an atomic number $25$ and an atomic symbol $\mathrm{Mn}$.
• It is a transition metal and belongs to Group-$7$ and the fourth period.

Electronic configuration of Manganese:

• The electronic configuration of $\mathrm{Mn}$ is $1{\mathrm{s}}^{2}2{\mathrm{s}}^{2}2{\mathrm{p}}^{6}3{\mathrm{s}}^{2}3{\mathrm{p}}^{6}3{\mathrm{d}}^{5}4{\mathrm{s}}^2$.
• $\mathrm{Mn}$ loses two electrons and forms ${\mathrm{Mn}}^{2+}$ion. Thus the electronic configuration of ${\mathrm{Mn}}^{2+}$ is $1{\mathrm{s}}^{2}2{\mathrm{s}}^{2}2{\mathrm{p}}^{6}3{\mathrm{s}}^{2}3{\mathrm{p}}^{6}3{\mathrm{d}}^5$.
• Thus, the number of unpaired electrons in ${\mathrm{Mn}}^{2+}$ion is $5$.