Question

What is the nth term of H.P with first 2 terms as $\frac{4}{11}$ and $\frac{2}{3}$ ?

• A.
• B.
• C.
• D.

Answer 1

The correct option is C

Given $\frac{4}{11}$, $\frac{2}{3}$ form H.P.

$\Rightarrow$ $\frac{11}{4}$, $\frac{3}{2}$ form A.P.

Common difference = D = $\frac{3}{2}$ - $\frac{11}{4}$ =$\frac{-5}{4}$

nth term of H.P. = $\frac{1}{a+(n-1)d}$

[Where a is first term of corresponding A.P. and D is common difference]

= $\frac{1}{\frac{11}{4}+(n-1)\frac{-5}{4}}$ = $\frac{4}{16-5n}$