What is the nth term of the sequence 1, 5, 9, 13, 17, ... ?

2n - 1

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2n + 1

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4n - 3

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None of the above

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Solution

The correct option is C 4n - 3
Given series is $1, 5, 9, 13, 17, . . .$
Common difference $(d) = 5 - 1 = 4$
First term is $a = 1$
So $n^{t h}$ term is $t_{n} = a + (n - 1) d = 1 + (n - 1) 4 = 4 n - 3$
$∴ t_{n} = 4 n - 3$

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