MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Oxidation States of Lanthanides

What is the n...

Question

What is the number of angular nodes in the second excited state of a hydride ion?

A

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $1$
The hydride ion is $H^{-}$
The electronic configuration of first excited state is $1 s^{1} 2 s^{1}$
The electronic configuration of second excited state is $1 s^{1} 2 s^{0} 2 p^{1}$

Suggest Corrections

thumbs-up

0

Similar questions

Q. Not considering electronic spin, the degeneracy of second excited state (

n = 3

H

9

, while the degeneracy of fourth excited state of hydride ion (

H^{-}

Q. Angular momentum in second Bohr orbit of H-atom is

x

. Then find out angular momentum in 1st excited state of

{L i}^{+ 2}

Q. For a hydrogen like ion

H e^{+}

, there is a dumb-belled symmetric state A with 2 radial nodes in excited state. The final state after de-excitation was found to be ground state of H - atom.
How many electrons with spin quantum number

m_{s} = - \frac{1}{2}

can be placed in A?

Q. The angular momentum of an electron in the

2^{n d}

excited state ofa Helium ion

(H e^{+})

Q. The binding energy of the second excited state of

L i^{2 +}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Lanthanoids

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Oxidation States of Lanthanides

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon