What is the number of chloride ions present in 1/2 mole of $M g C l_{2}$ ?

N_{A}

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2 N_{A}

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4 N_{A}

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\frac{N_{A}}{2}

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Solution

The correct option is D $N_{A}$
1 mole of $M g C l_{2}$ contains 2 moles of chloride ions.
So, 0.5 mole of $M g C l_{2}$ would contain 1 mole of cholride ions. i.e. $N_{A}$ chloride ions.
Where, $N_{A}$ = Avogadro's Number

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