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Question

What is the number of non-zero terms in the expansion of (1+23x)11+(123x)11 (after simplification)

A
4
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B
5
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C
6
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D
11
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Solution

The correct option is C 6
Given : (A)(1+23x)11+(B)(123x)11
General term of A
Tr+1=11Cr(1)11r(23x)r
General term of B
Tr+1=11Cr(1)11r(23x)r(1)x
All the terms, in which r=odd will cancel out each other, therefore no. of non-zero terms
T1,T3,T5,T7,T9,T11
Total=6.

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