The correct option is D 42
There are 3 trips parallel to AB and 3 strips parallel to AC. There are 6 horizontal parallelograms in the first. 3 in the second and 1 in the third strip parallel to AB. Kite shaped parallelograms in these strips are 6+3+1=10.
The pattern is repeated for strips parallel to AC except that topmost kite is common to both type of strips. There are 3 parallelograms each made up of 4 small parallelograms (horizontal and kite shaped.)
Hence total no. of parallelograms =[2(10+10)−1]+3=42.