Question

What is the number of total isomers including stereoisomers that have the formula $CoCr(N{H}_3{)}_{6}C{l}_6$. (All are ionic salts that have $C{o}^{3+}$ and $C{r}^{3+}$ as central atoms with octahedral geometry and $N{H}_3$ and $C{l}^{-}$ as ligands)

Answer 1

$\underset{\left(1\right)}{\left[Co\right(N{H}_3{)}_6\left]\right[Cr\left(Cl{)}_6\right]}$

$\underset{\left(1\right)}{\left[Co\right(N{H}_3{)}_{5}Cl\left]\right[Cr\left(N{H}_3\right)\left(Cl{)}_5\right]}$

$\underset{\left(\text{4 stereoisomers}\right)}{\left[Co\right(N{H}_3{)}_{4}C{l}_2\left]\right[Cr\left(N{H}_3{)}_2\right(Cl{)}_4]}$

$\underset{\left(1\right)}{\left[Cr\right(N{H}_3{)}_6\left]\right[Co\left(Cl{)}_6\right]}$

$\underset{\left(1\right)}{\left[Cr\right(N{H}_3{)}_{5}Cl\left]\right[Co\left(N{H}_3\right)\left(Cl{)}_5\right]}$

$\underset{\left(\text{4 stereomers}\right)}{\left[Cr\right(N{H}_3{)}_{4}C{l}_2\left]\right[Co\left(N{H}_3{)}_2\right(Cl{)}_4]}$

Note: $\left[Co\right(N{H}_3{)}_{3}C{l}_3\left]\right[Cr\left(N{H}_3{)}_{3}C{l}_3\right]$ is a neutral complex so it cannot be included here.