Question

What is the number of ways that 4 boys and 3 girls can be seated so that boys and girls alternate ?

• A. 12
• B. 72
• C. 120
• D. 144

Answer 1

Answer: (D)

144

The only pattern in which they can sit according to the given situation is,

$BGBGBGB$

Now boys can be arranged among themselves in $4!$ ways, and girls among themselves in $3!$ ways,

So total no. of ways $=4!\times 3!$

$=144$

Hence, option D is correct.