What is the OH ion concentration in the final solution prepared by mixing 20 mL of 0.050 M HCl with 30 mL of 0.10 M barium hydroxide?

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Solution

H+ ions present in HCl solution:
20.0/1000 * 0.050 = 0.001 moles

There are two OH- ions in a molecule of Ba (OH)2.
OH- ions released in the Barium Hydroxide solution =
= 2 * 30.0/1000 * 0.10 = 0.006 moles

So 0.001 moles of H+ and OH- combine to form water.

So 0.005 moles of OH- remain. So the molarity of [ OH- ]
= 0.005 moles / (20+30) ml =0.100 M

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