Question

What is the orbital angular momentum of an electron in ${}^{\prime }{f}^{\prime }$ orbital?

• A. $\frac{1.5h}{\pi }$
• B. $\frac{\sqrt{6}h}{\pi }$
• C. $\frac{\sqrt{3}h}{\pi }$
• D. $\frac{\sqrt{3}h}{2\pi }$

Answer 1

Answer: (C)

$\frac{\sqrt{3}h}{\pi }$

Orbital angular momentum,
$mvr=\frac{h}{2\pi }\sqrt{l(l+1)}$

For $f$-orbital, $l=3$

$\therefore$ Orbital angular momentum,

$mvr=\frac{h}{2\pi }\sqrt{3(3+1)}=\frac{\sqrt{3}h}{\pi }$

Hence, option $C$ is correct.