What is the order of basic nature of hydrides of $V A$ group elements?

A s H_{3} > S b H_{3} > P H_{3} > N H_{3}

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N H_{3} > S b H_{3} > P H_{3} > A s H_{3}

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N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

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P H_{3} > N H_{3} > S b H_{3} > A s H_{3}

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Solution

The correct option is C $N H_{3} > P H_{3} > A s H_{3} > S b H_{3}$
Basicity of hydrides of $N_{2}$ group decreases down the group due to decrease in electronegativity and increase in atomic size from $N_{2}$ to $B i$ .

So correct order of basicity is $N H_{3} > P H_{3} > A s H_{3} > S b H_{3}$ .

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Similar questions

1. S b H_{3} > N H_{3} > A s H_{3} > P H_{3}

2. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

3. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

4. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

1. S b H_{3} > N H_{3} > A s H_{3} > P H_{3}

2. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

3. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

4. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

Out of NH₃, PH₃, AsH₃ and SbH₃ the most basic hydride is:

N H_{3}, P H_{3}, A s H_{3}, S b H_{3}

N H_{3}, P H_{3}, A s H_{3}, S b H_{3}

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