Question

What is the order of magnitude of the seconds present in a day?

Answer 1

Given,

$1day=24hour$

$1hour=60min$

$1min=60\sec$

$1day=24\times 60\times 60=86400\sec$

$N=a\times {10}^b$

Where, $\frac{\sqrt{10}}{10}\le a<\sqrt{10}$ and

Then, represents the order of magnitude of the number.

$1day=0.864\times {10}^5\sec$

Hence, the order of magnitude is $5$.