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Quantitative Aptitude

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Question

What is the output printed by the following program?
#include < stdio.h>
int f(int n, int k)
{
if (n = = 0) return 0;
else if (n% 2) return f(n/2, 2k)+k;
else return f(n/2, 2k)- k;
}
int main( )
{
printf("%d", f(20, 1));
return 0;
}

A

20

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B

5

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C

9

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D

8

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Solution

The correct option is C 9

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Similar questions

Q. What is the value printed by the following C program?
#include <stido.h>
int f (int *a, int n)
{
if (n <= 0) return 0;
else if (*a % 2 == 0)
return *a + f(a + 1, n - 1);
else return *a -f(a + 1, n - 1);
}
int main ( )
{
int a [ ] = {12, 7, 13, 4, 11, 6};
printf("%d", f(a,6));
return 0;
}

Q. Consider the following C- program
void foo (int n, int sum) {
int k = 0, j = 0;
if (n = = 0) return;
k = n% 10;
j = n/10;
sum = sum + k;
foo (j, sum);
printf("%d", k);
}
int main () {
int a = 2048, sum = 0;
foo (a, sum);
printf ('&d\n", sum);
}
What does the above program print?

Q. Consider the program below:
# include <stdio.h>
int fun (int n, int *f_p) {
int t, f;
if(n< =1){
*f_p = 1;
return 1;
}
t = fun(n-1, f_p);
f = t +* f_p;
*f_p = t:
return f ;
}
int main()
{
int x = 15;
printf (“% d\n”, fun (5, &x)) ;
return 0;
The value printed is

Q. What does the following program print?
#include < stdio.h>
void f(int *p, int *q)
{
p = q;
*p = 2;
}
int i = 0, j = 1;
int main( )
{
f(&i, &j);
printf ("%d %d\n", i, j);
return 0;
}

Q. Consider the following two functions;
void fun1 (int n)
{ if (n = = 0) return ;
print("%d", n);
fun2 (n-2);
printf("%d", n);
}
void fun2 (int n)
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printf("%d", n);
fun1 (++ n);
printf ("%d", n);
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The output printed when fun 1 (5) is called is

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