What is the oxidation number of central atom in [Co(NH $_{3}$ ) $_{2}$ (NO $_{2}$ ) $_{4}$ ] $^{Θ}$ ?

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Solution

Let X be the oxidation number of central atom in [Co(NH $_{3}$ ) $_{2}$ (NO $_{2}$ ) $_{4}$ ] $^{Θ}$ .
$X + 2 (0) + 4 (- 1) = - 1$
$X = + 3$
Thus, the oxidation number of central atom in [Co(NH $_{3}$ ) $_{2}$ (NO $_{2}$ ) $_{4}$ ] $^{Θ}$ is +3.

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