What is the oxidation number of $C r$ in $K_{2} C r_{2} O_{7}$ ?

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Solution

Let the Ox. no. of $C r$ in $K_{2} C r_{2} O_{7}$ be x.
We know that, Ox. no. of $K = + 1$
Ox. no. of O $= - 2$
So, $2 (O x . n o . K) + 2 (O x . n o . C r) + 7 (O x . n o . O) = 0$
$2 (+ 1) + 2 (x) + 7 (- 2) = 0$
or $+ 2 + 2 x - 14 = 0$
or $2 x = + 14 - 2 = + 12$
or $x = + \frac{12}{2} = + 6$
Hence, oxidation number of $C r$ in $K_{2} C r_{2} O_{7}$ is $+ 6$ .

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