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Question

What is the oxidation number of Cr in Na2Cr2O7?

A
6
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B
2
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C
16
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D
10
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Solution

The correct option is A 6
Oxidation state of Na is +1 and oxygen is -2.
Thus,
2×(+1)+2×(x)+7×(2)=02+2x14=02x12=0x=+6

Hence, option (b) is correct.

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