Question

What is the oxidation number of $Fe$ in $F{e}_{0.94}O$?

Answer 1

Let the oxidation number of $Fe$ in ${Fe}_{0.94}O$ be $x$.

The oxidation number of O is -2

$\therefore$ $0.94x-2=0$

$\therefore$ $0.94x=+2$

$\therefore$ $x=\frac{+2}{0.94}$

$\therefore$ $x=+\frac{200}{94}$

Therefore, the oxidation number of $Fe$ in ${Fe}_{0.94}O$ is $+\frac{200}{94}$.