Question

what is the Oxidation number of $Fe$ in ${\left[Fe{\left(H_{2}O\right)}_{5}NO\right]}^{2+}$ due to charge transfer from $NO$ to ${Fe}^{2+}$.

• A. 1
• B. 2
• C. 3
• D. 4

Answer 1

The correct option is A 1

Let $x$ be the oxidation number of iron in ${\left[Fe{\left(H_{2}O\right)}_{5}NO\right]}^{2+}$.
Since the overall
charge on the complex is $2+$, the sum of oxidation states of all elements in
it should be equal to $2+$.
Therefore, $x+5\left(0\right)+1=2$
$x=+1$
Thus, oxidation number of $Fe$ in $\left[Fe{\left(H_{2}O\right)}_{5}NO\right]$ is $+1$ due to charge transfer from $NO$ to ${Fe}^{2+}$ ($NO$ becomes $N{O}^{+}$).