Question

What is the oxidation number of lead in $Pb{F}_2$?

• A. $0$
• B. $+2$
• C. $+1$
• D. $-1$

Answer 1

The correct option is B $+2$

$Pb{F}_2$

The total charge present is $0$.

Oxidation no. of Fluorine is $-1$.

Oxidation no. of lead be $x$.

So, $x+2(-1)=0x-2=0x=2$

So, oxidation no. of lead in $Pb{F}_2$ is $+2$.