Question

What is the oxidation number of $\mathrm{N}$ in $\mathrm{NO}$?

Answer 1

Oxidation number: Oxidation number denotes the oxidation state of an element in a compound ascertained according to a set of rules formulated on the basis that electron pair in a covalent bond belongs entirely to a more electronegative element.

Calculating the oxidation number of Nitrogen(N) in $\mathrm{NO}$:

The oxidation state of Oxygen(O) = -2

Consider the oxidation state of nitrogen(N) = x

Now,

$$\begin{gathered} x-2=0 \\ x=+2 \end{gathered}$$

Hence, the oxidation number of $\mathrm{N}$ in $\mathrm{NO}$ is $+2$.