What is the oxidation number of phosphorus in $H_{4} P_{2} O_{7}$ ?

+ 5

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- 5

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+ 4

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+ 3

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Solution

The correct option is A $+ 5$
Let the oxidation number of $P$ in $H_{4} P_{2} O_{7}$ be $x$
Then,
$4 + 2 x - 14 = 0$
$\Rightarrow x = + 5$

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