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Question

What is the oxidation number of Si in the compound CaSiO3?

A
4
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B
+2
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C
2
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D
+4
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Solution

The correct option is D +4
CaSiO3
Total charge present =0.
Oxidation no. of Oxygen is 2.
Oxidation no. od Calcium is +2.
Let, oxidation no. of Slilicon be X.
So, [+2]+x+3[2]=02+x6=0x=4
So, oxidation number of silicon in CaSiO3 is +4.

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