What is the oxidation number of underlined element?

$N a N - - O_{2}$

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Solution

Let the oxidation number of N in $N a N - - O_{2}$ be $x$ .
Since the overall charge on the compound is $0$ , the sum of oxidation states of all elements in it should be equal to $0$ .
Therefore, $+ 1 + x + 2 (- 2) = 0$
Hence, $x = + 3$
Thus, the oxidation number of N in $N a N - - O_{2}$ is $+ 3$ .

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