What is the oxidation number of underlined element?

${M g - -- -}_{3} N_{2}$

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Solution

Let $x$ be the oxidation number of Mg in $M g_{3} - --- - N_{2}$ .
Since the overall charge on the compound is $0$ , the sum of oxidation states of all elements in it should be equal to $0$ .
Therefore, $3 x + 2 (- 3) = 0$
or, $x = + 2$
Hence, the oxidation number of Mg in ${M g - -- -}_{3} N_{2}$ is $+ 2$ .

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