What is the oxidation number of underlined element?

${S - -}_{2} C l_{2}$

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Solution

Let the oxidation number of $S$ in $S_{2} C l_{2}$ be $x$ .
Since the overall charge on the complex is $0$ , the sum of oxidation states of all elements in it should be equal to $0$ .
Therefore, $2 x + 2 (- 1) = 0$
or, $x = + 1$
Hence, the oxidation number of $S$ in $S_{2} C l_{2}$ is $+ 1$ .

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