What is the oxidation state of central atom in $[N i (C O)_{4}]$ ?

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Solution

The correct option is A $0$
$[N i {(C O)}_{4}]$
Central atom $= N i$
Oxidation state of $C O$ in general $= 0$
Applying formula, $Sum of total oxidation state of all atoms = Overall charge on the compound .$
Let oxidation state of $N i = x x + 4 (0) = 0, x = 0$
$∴$ Oxidation state of $N i = 0.$

Suggest Corrections

	Column I ( Complex)		Column II ( Oxidation state of central atom )
(A)	$K_{3} [C O (C_{2} O_{4})_{2} C l_{2}]$	(i)	$0$
(B)	$[P t (C_{2} H_{4} C l_{3}]^{-}$	(ii)	$+ 1$
(C)	$[F e (H_{2} O)_{5} N O] S O_{4}$	(iii)	$+ 3$
(D)	$[N i (C O)_{4}]$	(iv)	$+ 2$