Question

What is the oxidation state of coloured ion in $Mn{O}_4^{2-}$?

Answer 1

The given compound is $Mn{O}_4^{2-}$

Let oxidation state of $Mn$ be $x$.

Charge of oxygen atom is $-2$.

By putting the values, we get:

$x-2\times 4=-2$

$⟹x=+6$

So, the correct answer is +6.