What is the oxidation state of copper in the compound, $Y B a_{2} C u_{3} O_{7}$ which shows super conductivity? Assume that the rare earth element, yttrium is in its usual $+ 3$ oxidation state.

\frac{7}{3}

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Solution

The correct option is A $\frac{7}{3}$
Let $x$ be the oxidation state of Cu.
For a neutral compound, sum of oxidation states of all elements is equal to zero.
Hence, $3 + 2 \times 2 + 3 x + 7 \times (- 2) = 0$
or, $x = \frac{7}{3}$
Thus, the oxidation state of copper is $\frac{7}{3}$ .

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Similar questions

The compound Y $B a_{2} C u_{3} O_{7}$ which shows superconductivity has copper in oxidation state ........ Assume that the rare earth element Yttrium is in its usual +3 oxidation state

State whether the given statement is true or false:

The compound

Y {B a}_{2} {C u}_{3} O_{7}

which shows super conductivity has copper in oxidation state

+ \frac{7}{3}

. Assume that the rare earth element yttrium is in its usual

+ 3

oxidation state.

The compound Y $B a_{2} C u_{3} O_{7}$ which shows superconductivity has copper in oxidation state ........ Assume that the rare earth element Yttrium is in its usual +3 oxidation state

Q. The compound

Y B a_{2} C u_{3} O_{7}

, which shows super conductivity has copper in oxidation state of

\frac{7}{3}

.
Assume that the rare earth element ytterbium is in its usual

+ 3

oxidation state.
If true enter 1, else enter 0.

Q. In the compound

Y {B a}_{2} {C u}_{3} O_{7}

which shows superconductivity, what is the oxidation state of

C u

?
Assume that the rare earth element yttrium is in its usual +3 oxidation state.

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What is the oxidation state of copper in the compound, YBa2Cu3O7 which shows super conductivity? Assume that the rare earth element, yttrium is in its usual +3 oxidation state.

The correct option is A 73Let x be the oxidation state of Cu.For a neutral compound, sum of oxidation states of all elements is equal to zero.Hence, 3+2×2+3x+7×(−2)=0or, x=73Thus, the oxidation state of copper is 73.

What is the oxidation state of copper in the compound, $Y B a_{2} C u_{3} O_{7}$ which shows super conductivity? Assume that the rare earth element, yttrium is in its usual $+ 3$ oxidation state.

The correct option is A $\frac{7}{3}$
Let $x$ be the oxidation state of Cu.
For a neutral compound, sum of oxidation states of all elements is equal to zero.
Hence, $3 + 2 \times 2 + 3 x + 7 \times (- 2) = 0$
or, $x = \frac{7}{3}$
Thus, the oxidation state of copper is $\frac{7}{3}$ .