Question

What is the oxidation state of the underlined atoms in the compound $\underset{–}{Cr}{O}_{2}C{l}_2$?
(answer is the modulus of oxidation state)

Answer 1

Let the oxidation state of Cr in $\underset{–}{Cr}{O}_{2}C{l}_2$ be $x$.
$x+2(-2)+2(-1)=0$
$x=+6$
Hence, the oxidation state of Cr in $\underset{–}{Cr}{O}_{2}C{l}_2$ is +6.