What is the oxidizing agent in the following equation?
$H A s O_{2} (a q) + S n^{2 +} (a q) + H^{+} (a q) \to A s (s) + S n^{4 +} (a q) + H_{2} O (l)$

H A s O_{2} (a q)

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S n^{2 +} (a q)

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H^{+} (a q)

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S n^{4 +} (a q)

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Solution

The correct option is A $H A s O_{2} (a q)$
An oxidizing agent is a compound or element which itself undergoes reduction. In the given reaction oxidation no. of $A s$ in $H A s O_{2}$ is +3, which gets reduced to 0 in $A s$ (s). Thus it undergoes reduction and acts as an oxidizing agent.

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