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Byju's Answer
Standard X
Chemistry
Double Displacement Reaction
What is the o...
Question
What is the oxidizing agent in the following redox reaction?
Z
n
(
s
)
+
C
u
2
+
(
a
q
)
⟶
Z
n
2
+
(
a
q
)
+
C
u
(
s
)
A
C
u
2
+
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B
Z
n
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C
both A and B
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D
none of the above
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Solution
The correct option is
A
C
u
2
+
∵
C
u
2
+
is undergoing reduction to
C
u
(
s
)
so
C
u
2
+
is the oxidising agent.
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Similar questions
Q.
C
u
2
+
(
a
q
)
+
Z
n
(
s
)
→
Z
n
2
+
(
a
q
)
+
C
u
(
s
)
In the above reaction which of the following is reduced?
Q.
Calculate
E
o
C
e
l
l
value of the following reactions:
Z
n
(
s
)
+
C
u
2
+
(
a
q
)
→
Z
n
2
+
(
a
q
)
+
C
u
(
s
)
[Given:
E
∘
C
u
2
+
/
C
u
=
0.34
V
,
E
∘
Z
n
2
+
/
Z
n
=
−
0.76
V
]
Q.
E
∘
for the cell,
Zn(s)|Zn
2
+
(
aq
)
|
|
Cu
2
+
(aq)|Cu(s)
is
1.10
V at
25
∘
C
. The equilibrium constant for the reaction,
Zn(s)
+
Cu
2
+
(aq)
→
Cu(s)
+
Zn
2
+
(aq)
is
1.94
×
10
x
. The value of
x
is
Q.
Calculate
E
∘
values of following reactions:
C
u
(
s
)
+
Z
n
2
+
(
a
q
)
→
Z
n
(
s
)
+
C
u
2
+
(
a
q
)
[Given:
E
0
C
u
2
+
/
C
u
=
0.34
V
,
E
0
Z
n
2
+
/
Z
n
=
−
0.76
V
]
Q.
E
∘
for the cell is
Z
n
|
Z
n
2
+
(
a
q
)
|
|
C
u
2
+
(
a
q
)
|
C
u
at
25
∘
C
, the equilibrium constant for the reaction
Z
n
+
C
u
2
+
(
a
q
)
⇌
C
u
+
Z
n
2
+
(
a
q
)
is of the order of
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