You visited us 1 times! Enjoying our articles? Unlock Full Access!

Properties of Alpha, Beta and Gamma Radiations

What is the p...

Question

What is the particle $X$ in the following nuclear reaction?
$_{4}^{9} B e +_{2}^{4} H e ⟶_{6}^{12} C + X$

Electron

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Proton

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Photon

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Neutron

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is C Neutron
$_{4}^{9} B e +_{2}^{4} H e ⟶_{6}^{12} C +_{Z}^{A} X$
Comparing sum of mass numbers and atomic numbers on both sides, we get
$A = 1, Z = 0$
Hence, $X$ represents $_{0}^{1} n$ (neutron).

Suggest Corrections

Similar questions

_{4}^{9} B e +_{2}^{4} H e ⟶_{6}^{12} C + X

X

_{4}^{9} B e +_{2}^{4} H e ⟶_{6}^{12} C +_{0}^{1} n

X

_{5}^{B} 10

_{2}^{H e} 4

⟶

_{7}^{N} 13

X

X

_{7}^{13} N

⟶

_{6}^{13} C +

_{1}^{0} e

X

_{96}^{246} C m +_{6}^{12} C ⟶ ? + 4_{0}^{1} n

Join BYJU'S Learning Program