What is the path difference of destructive interference :

n λ

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n (λ + 1)

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\frac{(n + 1) λ}{2}

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\frac{(2 n + 1) λ}{2}

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Solution

The correct option is D $\frac{(2 n + 1) λ}{2}$
For destructive interference
Intensity should be minimum

$I = I_{1} + I_{2} + 2 \sqrt{I_{1} I_{2}} cos ϕ$

$\Rightarrow cos ϕ = - 1 = (\frac{2 n + 1}{2}) π = ϕ$

$\Rightarrow Δ x = (\frac{2 n + 1}{2}) λ$

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Similar questions

Q. Match the condition for the type of interference:
1. Constructive I.

(2 n + 1) \frac{λ}{2}

2. Destructive II.

(2 n) λ

Q. The value of

lim n \to \infty {[{(\frac{n + 1}{n})}^{λ} . {(\frac{n + 2}{n})}^{λ} . . . . . . . . .]}^{1 / n}

Q. What is the path difference for destructive interference?

Two coherent waves represented by $y_{1} = A sin (\frac{2 π x_{1}}{λ} - ω t + \frac{π}{6})$ and $λ_{2} = A sin (\frac{2 π x_{2}}{λ} - ω t + \frac{π}{8})$ are superposed. The path difference $(x _{1} - x_{2})$ to produce constructive interference $(n ϵ I)$ .

In videos destructive interference is given (2n+ 1)lambda/2 where as in board book it is given by (2n - 1)lambda/2. Which of these is correct for destructive interference?

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What is the path difference of destructive interference :

The correct option is D (2n+1)λ2For destructive interference Intensity should be minimumI=I1+I2+2√I1I2cosϕ⇒cosϕ=−1=(2n+12)π=ϕ⇒Δx=(2n+12)λ

The correct option is D $\frac{(2 n + 1) λ}{2}$
For destructive interference
Intensity should be minimum

$I = I_{1} + I_{2} + 2 \sqrt{I_{1} I_{2}} cos ϕ$

$\Rightarrow cos ϕ = - 1 = (\frac{2 n + 1}{2}) π = ϕ$

$\Rightarrow Δ x = (\frac{2 n + 1}{2}) λ$