Question

What is the orbital velocity of Jupiter?

Answer 1

Step 1: Given data:

The distance between sun and jupiter $\left(r\right)=7.8\times {10}^{11}m$

Mass of sun $\left(M\right)=2\times {10}^{30}kg$

Gravitational constant$\left(G\right)=6.7\times {10}^{-11}N{m}^2/k{g}^2$

Step 2: Formula Used:

The orbital velocity of jupiter around the sun is $v=\sqrt{\frac{GM}{r}}$

Step 3: Calculation:

By putting all the above values in the formula,we get

$\begin{array}{rcl}v& =& \sqrt{\frac{6.7\times {10}^{-11}\times (2\times {10}^{30})}{(7.8\times {10}^{11})}}\\ & =& \sqrt{1.718\times {10}^8}\\ & =& 1.3\times {10}^{4}m/secor13km/sec.\end{array}$

Hence, the orbital velocity of jupiter is $1.3\times {10}^{4}m/secor13km/sec$.