What is the percent composition of oxygen in $C_{6} H_{12} O_{6}$ (molar mass = 180)?

25%

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33%

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40%

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53%

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75%

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Solution

The correct option is D 53%
Total molar mass of O-atoms present in $C_{6} H_{12} O_{6} = 6 \times 16 = 96 g / m o l$
Percentage composition = $\frac{96}{180} \times 100 = 53.33$ %

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