Question

What is the percent yield of the following reaction if $50g$ of CaCO₃ is heated to give $15g$ of CaO?
$CaC{O}_3\to CaO+C{O}_2$

• A. 44.6%
• B. 50.0%
• C. 66.6%
• D. 53.5%

Answer 1

The correct option is D 53.5%

For the given reaction,
$CaC{O}_3\to CaO+C{O}_2$
As per stoichiometry, $1$ mol of $CaC{O}_3$ decomposes to give $1$ mol of $CaO$ and $1$ mol of $C{O}_2$
$InitialmolesofCaC{O}_3=\frac{50}{100}=0.5mol$
So, theoretically,

$molesofCaOproduced=0.5mol$
$\therefore massproduced=0.5\times molarmassofCaO=0.5\times 56=28g$

But actual yield is $15g$ of $CaO$

So, $Percentageyield=\frac{Actualyield}{Theoreticalyield}\times 100$
$=\frac{15g}{28g}\times 100\simeq 53.5$%