What is the percentage by weight of sulphuric acid if 13 g of H $_{2}$ SO $_{4}$ is dissolved to make 78 g of solution?

13.2%

No worries! We‘ve got your back. Try BYJU‘S free classes today!

14.28%

No worries! We‘ve got your back. Try BYJU‘S free classes today!

20%

No worries! We‘ve got your back. Try BYJU‘S free classes today!

16.6%

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D 16.6%
Weight of sulphuric acid = 13g
Weight of solution = 78g
Therefore w/W% = $\frac{13}{78} \times 100$ = 16.6%

Suggest Corrections

Similar questions

H_{2} S O_{4}

9.8 g

H_{2} {S O}_{4}

250 g

H_{2} S O_{4}

H_{2} S O_{4}

H_{2} S O_{4}

From the equation:

C + 2H₂SO₄ → CO₂+ 2H₂O +2SO₂

Calculate:

The mass of carbon oxidized by 49 g of sulphuric acid (C = 12; relative molecular mass of sulphuric acid = 98).

H_{2} S O_{4} + 2 N a O H (a q) \to 2 H_{2} O (l) + N a_{2} S O_{4} (a q)

Join BYJU'S Learning Program