What is the percentage compositions of hydrogen and oxygen in water $(H_{2} O)$ ? $(H = 1, O = 16)$

11.1, 88.90

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12.3, 18.32

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15.6, 94.86

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34.3, 60.55

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Solution

The correct option is A 11.1, 88.90
Molecular mass of $H_{2} O = 2 + 16 = 18 g$
As there are 2 hydrogen atoms in 1 mole of water ; Molar mass of H in 1 mole of $H_{2} O = 1 \times 2 = 2 g$
Therefore %age of H in $H_{2} O$ $= \frac{2}{18} \times 100 = 11.1$ %
Also molar mass of O in 1 mole of $H_{2} O$ $= 16 g$ Therefore %age of O in $H_{2} O$ $= \frac{16}{18} \times 100 = 88.9$ %

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What is the percentage compositions of hydrogen and oxygen in water (H2O)? (H=1,O=16)

The correct option is A 11.1, 88.90Molecular mass of H2O=2+16=18gAs there are 2 hydrogen atoms in 1 mole of water ; Molar mass of H in 1 mole of H2O=1×2=2gTherefore %age of H in H2O =218×100=11.1%Also molar mass of O in 1 mole of H2O =16g Therefore %age of O in H2O =1618×100=88.9%

What is the percentage compositions of hydrogen and oxygen in water $(H_{2} O)$ ? $(H = 1, O = 16)$