What is the percentage decrease in the number of boys who passed in the exam from university D in the year 2009 in comparison to the previous year?

12.5 %

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3.8 %

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7.5 %

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15.8 %

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None of these

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Solution

The correct option is A $12.5 %$
Decrease in the number of boys who passed $= (9.6 - 8.4) t h o u s a n d = 1.2 t h o u s a n d$
$∴$ required percentage decrease $= \frac{1.2}{9.6} \times 100 = 12.5 %$

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Similar questions

Q. The number of girls passing the exam from university B in the year 2006 is approximately what percentage of the number of boys passing the exam from university A in the year 2010?

Study the table carefully to answer the questions that follow:

Table shows the number of Students (in thousands) passed in an examination held in five different Universities in six years

$\begin{matrix} Y e a r & A & B & C & D & E B o y s ∣ G i r l s & B o y s ∣ G i r l s & B o y s ∣ G i r l s & B o y s ∣ G i r l s & B o y s ∣ G i r l s 2005 & 12.4 ∣ 8.3 & 14.3 ∣ 8.4 & 4.3 ∣ 3.4 & 4.7 ∣ 2.1 & 9.8 ∣ 3.1 2006 & 11.6 ∣ 6.4 & 8.9 ∣ 7.2 & 4.9 ∣ 4.3 & 5.8 ∣ 4.3 & 7.3 ∣ 4.3 2007 & 13.7 ∣ 7.8 & 7.6 ∣ 4.8 & 5.8 ∣ 6.8 & 9.3 ∣ 6.3 & 8.4 ∣ 3.2 2008 & 18.4 ∣ 9.9 & 10.4 ∣ 8.4 & 7.4 ∣ 7.2 & 9.6 ∣ 4.4 & 4.6 ∣ 4.2 2009 & 14.8 ∣ 11.4 & 9.6 ∣ 7.2 & 8.9 ∣ 6.1 & 8.4 ∣ 5.2 & 6.8 ∣ 3.1 2010 & 18.2 ∣ 16.2 & 7.4 ∣ 5.2 & 11.8 ∣ 9.3 & 7.3 ∣ 5.1 & 7.8 ∣ 6.3 \end{matrix}$

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What is the percentage decrease in the number of boys who passed in the exam from university D in the year 2009 in comparison to the previous year?

The correct option is A 12.5%Decrease in the number of boys who passed =(9.6−8.4) thousand=1.2 thousand ∴ required percentage decrease =1.29.6×100=12.5%

The correct option is A $12.5 %$
Decrease in the number of boys who passed $= (9.6 - 8.4) t h o u s a n d = 1.2 t h o u s a n d$
$∴$ required percentage decrease $= \frac{1.2}{9.6} \times 100 = 12.5 %$