What is the percentage of the total number of boys in standards fifth, sixth and seventh together with respect to the total number of girls in standards eighth, ninth and tenth together (rounded off to nearest integer)?

119

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117

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114

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Solution

The correct option is D
114

Required percentage = $\frac{(360 + 450 + 360)}{(270 + 320 + 432)} \times 100 = 114.5 %$

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What is the percentage of the total number of boys in standards fifth, sixth and seventh together with respect to the total number of girls in standards eighth, ninth and tenth together (rounded off to nearest integer)?

The correct option is D 114 Required percentage = (360+450+360)(270+320+432)×100=114.5%

The correct option is D
114

Required percentage = $\frac{(360 + 450 + 360)}{(270 + 320 + 432)} \times 100 = 114.5 %$