What is the perimeter of above triangle?

(x^{4} + 3 x^{3} + 2 x^{2} + 4)

units

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(x^{4} + 2 x^{2} + 4)

units

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(x^{4} + 3 x^{3} + 2 x^{2} + 4)

units

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(x^{4} + 3 x^{3} + 2 x^{2} + 2)

units

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $(x^{4} + 3 x^{3} + 2 x^{2} + 4)$ units

As given in the hint, the perimeter of a triangle is equal to the sum of the lengths of all its sides.

$\Rightarrow$ Perimeter $= (3 x^{4} - 5 x^{2} + 2) + (3 x^{3} + 6 x^{2} - 4) + (- 2 x^{4} + x^{2} + 6)$
Combining the like terms

$= (3 x^{4} - 2 x^{4}) + 3 x^{3} + (- 5 x^{2} + 6 x^{2} + x^{2}) + (2 - 4 + 6)$

$= x^{4} + 3 x^{3} + 2 x^{2} + 4$

Therefore, perimeter of the given triangle is $(x^{4} + 3 x^{3} + 2 x^{2} + 4) - -------------------- -$ units.

Hence, option (a.) is the correct choice.

Suggest Corrections

Similar questions

What is the semi perimeter of the triangle?

T h e a r e a o f a n e q u i l a t e r a l t r i a n g l e i s \sqrt{3} .

W h a t i s t h e p e r i m e t e r o f t h e t r i a n g l e ?

C D E

A B C E

1

A B C D E

Join BYJU'S Learning Program