You visited us 1 times! Enjoying our articles? Unlock Full Access!

pH of a Solution

What is the ...

Question

What is the $p H$ of $0.005 (M) H_{2} S O_{4}$ solutions?

3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $2$
$H_{2} {S O}_{4}$ is a strong, diprotic acid. The equation for its ionization is
$H_{2} {S O}_{4 (a q)} ⟶ {2 H}^{+} + {S O}_{4}^{2 -}$
Since the equation tells us that each molecule of acid will produce $2$ hydrogen ions, the concentration of the $H^{+}$ ion must be $2$ x $0.0050 M$ or $0.010 M$
Using the definition of $p H$ =-log $H^{+}$ = $- l o g (0.010 M)$ = $2$

Suggest Corrections

Similar questions

Calculate the ph of 0.005M h2so4 solution ?

(p H_{1}),

(p H_{2}),

p H_{3})

p H_{4})

0.005 M H_{2} S O_{4}

H C l

p H = 3

p H = 5

p H

log (0.505) = - 0.3

100 m l

{N a}_{2} {C O}_{3}

5.3 g

{N a}_{2} {C O}_{3}

200 m l

H_{2} {S O}_{4}

H_{2} {S O}_{4}

l o g 5 = 0.6990

Join BYJU'S Learning Program