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Introduction and Degree of Hydrolysis

What is the p...

Question

What is the $p H$ of $0.01 M N a H C O_{3}$ ?
Given : $K_{a_{1}} a n d K_{a_{2}}$ for $H_{2} C O_{3}$ are $4.5 \times 10^{- 7} a n d 4.7 \times 10^{- 11}$ respectively at $25^{o} C$ .

A

5.66

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B

8.33

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C

10.57

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D

6.33

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Solution

The correct option is B 8.33
$p K_{a 1} = - log (K_{a 1}) p K_{a 1} = - log (4.5 \times 10^{- 7}) = 6.34$

$p K_{a 2} = - log (K_{a 2}) p K_{a 2} = - log (4.7 \times 10^{- 11}) = 10.32$

For an amphiprotic ion pH is calculated as:
$p H = \frac{1}{2} [p K_{a_{1}} + p K_{a_{2}}] p H = \frac{1}{2} [6.34 + 10.32] = 8.33$

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Similar questions

p H

0.01 M N a H C O_{3}

K_{a_{1}} a n d K_{a_{2}}

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4.5 \times 10^{- 7} a n d 4.7 \times 10^{- 11}

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K_{a 1} f o r H_{2} C O_{3} = 4.45 \times 10^{- 7}

K_{a 2} f o r H_{2} C O_{3} = 4.69 \times 10^{- 11}

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Introduction and Degree of Hydrolysis

Standard XII Chemistry

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