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Question

What is the pH of 0.5M aqueous solution of NaCN? Given pKb of CN = 4.70


A

5.6

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B

3.4

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C

8.8

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D

11.5

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Solution

The correct option is D

11.5


pKb of CN = 4.70

pKb + pKa = 14

pKa = 14.0 - 4.70 = 9.30

NaCN is a salt of a weak acid Vs strong base

PH = 12pKw + 12pKθ + 12logC

= 12 × 14 + 12 × 9.3 + 12 log 0.5

= 11.5


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