What is the pH of 0.5M aqueous solution of NaCN? Given pKb of CN− = 4.70
11.5
pKb of CN− = 4.70
pKb + pKa = 14
pKa = 14.0 - 4.70 = 9.30
NaCN is a salt of a weak acid Vs strong base
∴ PH = 12pKw + 12pKθ + 12logC
= 12 × 14 + 12 × 9.3 + 12 log 0.5
= 11.5