What is the pH of 1M HCN Ka - 4-8 - 10-11-

We know α = √(K_ac) = √(4.8 × 10^ 111) = 7 × 10^ 6 Here, α lt; lt; 1 nbsp; pH = log [√(K_aC)] ⇒ pH = log (√(4.8 × 10^ 11× 1)⇒ pH = log(7 × 10^ 6) ⇒ ...

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Standard XII

Chemistry

pH the Power of H

What is the p...

Question

What is the pH of 1M HCN $(K_{a} = 4.8 \times 10^{- 11})$ ?

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7.1

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5.2

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Solution

The correct option is D 5.2
we know $α = \sqrt{\frac{K_{a}}{c}} = \sqrt{\frac{4.8 \times 10^{- 11}}{1}} = 7 \times 10^{- 6}$
Here, $α << 1$
$p H = - l o g [\sqrt{K_{a} C}]$
$\Rightarrow p H = - l o g (\sqrt{4.8 \times 10^{- 11} \times 1}$ $\Rightarrow p H = - l o g (7 \times 10^{- 6})$
$\Rightarrow p H = - l o g 7 + 6$
$\Rightarrow p H = - 0.8 + 6 \Rightarrow p H = 5.2$

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What is the pH of 1M HCN (Ka=4.8×10−11)?

The correct option is D 5.2we know α=√Kac=√4.8×10−111=7×10−6 Here, α<<1 pH=−log[√KaC] ⇒pH=−log(√4.8×10−11×1⇒pH=−log(7×10−6) ⇒pH=−log 7+6 ⇒pH=−0.8+6⇒pH=5.2

What is the pH of 1M HCN $(K_{a} = 4.8 \times 10^{- 11})$ ?