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Question

What is the pH of 5×108 N HCl ?



A
5.95
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B
6.95
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C
6.5
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D
5.5
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Solution

The correct option is B 6.95
HClH++ Cl
[H+]from HCl=5×108H2OH++ OH (x+5×108) x[H+] [OH]=1014(x+5×108)x=1014(x+5×108)x1014=0x2+5×108x1014=0Solving, x=7.8×108pH=log10(x+5×108)pH=log10(7.8×108+5×108)pH=6.95

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