wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

What is the pH of a saturated solution of X(OH)3 will be if its solubility product = 2.7×1043?
[Given: log 3 = 0.5, log 2 = 0.3]

A
10.5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
7
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
3.5
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
3.8
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D 3.5
X(OH)3X++3OH
Ksp=[X+][OH]3
2.7×1043=s(3s)3=27s4
s=4Ksp/27=42.7×104327
=41044=(1044)1/4=1011
[OH]=3×1011M=pOH=log(3×1011)
pOH=(log3+log1011)=10.5
pH=1410.5=3.5

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
pH of a Solution
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon