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Question

What is the pH of a solution in which 10 mL of 0.1 M Sr(OH)2 is added to 10 mL of 0.1 M HCl ?
(Given: log5=0.7)

A
2.3
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B
1.5
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C
12.7
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D
7.0
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Solution

The correct option is C 12.7
Milli-equivalents of HCl=10×0.1=1
Milli-equivalents of Sr(OH)2=2×0.1×10=2
Concentration of remaining [OH]=2120=0.05
pOH=log[OH]=log(0.05)=1.3
pH=141.3=12.7

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