What is the pH of a solution in which 10 mL of 0.1 MSr(OH)2 is added to 10 mL of 0.1 MHCl?
(Given: log5=0.7)
A
2.3
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B
1.5
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C
12.7
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D
7.0
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Solution
The correct option is C12.7 Milli-equivalents of HCl=10×0.1=1
Milli-equivalents of Sr(OH)2=2×0.1×10=2
Concentration of remaining [OH]−=2−120=0.05 pOH=−log[OH−]=−log(0.05)=1.3 ∴pH=14−1.3=12.7